2sin^2(x)+sin(x)+1=0

Solution for 2sin^2(x)+sin(x)+1=0 equation:

Simplifying
2sin2(x) + sin(x) + 1 = 0

Multiply in2s * x
2in2sx + sin(x) + 1 = 0

Multiply ins * x
2in2sx + insx + 1 = 0

Reorder the terms:
1 + insx + 2in2sx = 0

Solving
1 + insx + 2in2sx = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + insx + -1 + 2in2sx = 0 + -1

Reorder the terms:
1 + -1 + insx + 2in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + insx + 2in2sx = 0 + -1
insx + 2in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
insx + 2in2sx = -1

Reorder the terms:
1 + insx + 2in2sx = -1 + 1

Combine like terms: -1 + 1 = 0
1 + insx + 2in2sx = 0

The solution to this equation could not be determined.